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(1/9)^3x=27^3x+1
We move all terms to the left:
(1/9)^3x-(27^3x+1)=0
Domain of the equation: 9)^3x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/9)^3x-(27^3x+1)=0
We get rid of parentheses
(+1/9)^3x-27^3x-1=0
We multiply all the terms by the denominator
(+1-27^3x*9)^3x-1*9)^3x=0
Wy multiply elements
(+1-27^3x*9)^3x-9x=0
We add all the numbers together, and all the variables
-9x+(+1-27^3x*9)^3x=0
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